Question
Download Solution PDFदी गई आकृति में, यदि PA और PB केंद्र O वाले वृत्त की स्पर्श रेखाएँ इस प्रकार हैं कि ∠APB = 54°, तो ∠OBA = ________।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
PA और PB केंद्र O वाले वृत्त पर स्पर्श रेखाएँ इस प्रकार हैं कि ∠APB = 54° है
गणना:
हम जानते हैं कि त्रिज्या और स्पर्श रेखा उनके संपर्क बिंदु पर लंबवत होती हैं।
इसलिए,
∠PAO = ∠PBO = 90°
इसलिए,
∠AOB = 360 - 54 - 180
⇒ 126°
साथ ही AO = OB = त्रिज्या
इसलिए, ∠OAB = ∠OBA = 54/2
⇒ 27°
∴ अभीष्ट उत्तर 27° है।
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