Question
Download Solution PDFसमीकरण x – y = 5 का आलेख y-अक्ष को P(α, β) पर प्रतिच्छेदित करता है और x + y = 5 का आलेख x-अक्ष को Q(γ, δ) पर प्रतिच्छेदित करता है। α + β + γ + δ का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया है:
दिए गए व्यंजक x - y = 5 और x + y = 5 हैं।
गणना:
हमारे पास है, x - y = 5 ----(1)
और, x + y = 5 ----(2)
चूंकि समीकरण (1) y-अक्ष पर प्रतिच्छेदित करता है, इसलिए x = 0
इसलिए, 0 - y = 5
⇒ y = -5
अतः, P(α, β) = (0, -5)
और, समीकरण (2) x-अक्ष पर प्रतिच्छेदित करता है, इसलिए y = 0
इसलिए, x + 0 = 5
⇒ x = 5
अतः, Q(γ, δ) = (5, 0)
अब, α + β + γ + δ = 0 + (-5) + 5 + 0
⇒ 0
∴ α + β + γ + δ का मान 0 है।
Last updated on Jun 25, 2025
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