If sin θ = \(1 \over 2\), then the value of (3cos θ - 4 cos3 θ) is:

This question was previously asked in
SSC CGL 2022 Tier-I Official Paper (Held On : 06 Dec 2022 Shift 3)
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  1. 0
  2. 1
  3. 2
  4. -1

Answer (Detailed Solution Below)

Option 1 : 0
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Detailed Solution

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Given:

sin θ = \(1 \over 2\)

Concept used:

Trigo

Calculation:

sin θ = \(1 \over 2\)

⇒ sinθ = sin 30°

So, θ = 30°

3cos θ - 4 cos3 θ

⇒ 3 × \(\sqrt3 \over 2\) - 4 × \(3\sqrt3 \over 8\)

⇒ \({3\sqrt3 \over 2} - \frac{3\sqrt3}{2}\)

⇒ 0

∴ The required answer is 0.

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