Question
Download Solution PDFIf the specific weight of a fluid is 19620 N/m3, then what will be its specific volume in m3/kg? (Take g = 9.81 m/sec2)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Density (ρ): It is the ratio of mass per unit volume.\(ρ=\frac{mass}{volume}⇒\frac{m}{V}\) kg/m3
Specific gravity (S.G): The specific gravity of a liquid is the relative weight of that liquid compared to an equal volume of water.
\(S.G= \frac{{Density\;of\;liquid}}{{Density\;of\;water}}⇒\frac{ρ}{ρ_w}\)
Specific volume (ν): It is the ratio of volume per unit mass.
\(\nu=\frac{volume}{mass}⇒\frac{V}{m}=\frac{1}{ρ}\) m3/kg
Calculation:
Given:
Specific weight = ρg = 19620 N/m3
∴ Density (ρ) = 19620/9.81 = 2000 kg/m3
\(\nu=\frac{1}{ρ} = \frac{1}{20000}=0.5\times10^-3\; m^3/kg\)
The specific volume of liquid is 0.5 × 10-3 m3/kg.
Last updated on May 28, 2025
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