Question
Download Solution PDFIn 1 kg. mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10% ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The percentage of iron in 1 kg of mixture is 20%
Calculation:
The amount of iron = 20/100 × 1000 = 200gm (1kg = 1000 gm)
The amount of sand = 1000 - 200 = 800 gm
Let the add amount of sand be x
According to the question;
⇒ 200/(1000 + x) = 10/100
⇒ 2000 = 1000 + x
⇒ x = 1000 gm = 1 kg
∴ The added amount of sand is 1 kg.
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