Question
Download Solution PDFPipe A can empty a tank in 48 minutes, Pipe B can fill the same tank in 72 minutes and Pipe C can fill the same tank in 96 minutes. If all three pipes are opened together, how many minutes will it take to fill the empty tank?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Pipe A = 48 minutes
Pipe B = 72 minutes
Pipe C = 96 minutes
Calculation:
In 1 minute Pipe A can fill = \(1 \over 48\)
In 1 minute Pipe B can fill = \(1 \over 72\)
In 1 minute Pipe C can fill = \(1 \over 96\)
In 1 minutes all three pipes can fill
⇒ \({1 \over 96} + {1 \over 72} - {1 \over 48}\)
⇒ \({4\; +\; 3\; -\; 6} \over 288\)
⇒ \(1 \over 288\)
⇒ Time taken = 1/ \(1 \over 288\) = 288 minutes
∴ All pipes together can fill the tank in 288 minutes.
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