Successive Discounts MCQ Quiz - Objective Question with Answer for Successive Discounts - Download Free PDF

Given:

Selling Price (SP) = ₹359625

Discounts = 25% and 30%

Formula used:

SP = MP × (1 - D1/100) × (1 - D2/100)

Where, MP = Marked Price

D1 = First Discount

D2 = Second Discount

Calculations:

₹359625 = MP × (1 - 25/100) × (1 - 30/100)

⇒ ₹359625 = MP × (0.75) × (0.70)

⇒ ₹359625 = MP × 0.525

⇒ MP = ₹359625 / 0.525

⇒ MP = ₹685000

∴ The correct answer is option (1).

Given:

Marked Price (MP) = ₹21,500

First Discount = 24%

Second Discount = 25%

Formula used:

Selling Price (SP) = MP × (1 - First Discount/100) × (1 - Second Discount/100)

Calculations:

SP = ₹21,500 × (1 - 24/100) × (1 - 25/100)

⇒ SP = ₹21,500 × 0.76 × 0.75

⇒ SP = ₹21,500 × 0.57

⇒ SP = ₹12,255

∴ The correct answer is option (4).

Given:

Marked price of the article = ₹21,600

First discount = 25%

Second discount = 26%

Formula used:

Selling Price after successive discounts = Marked Price × (1 - Discount1) × (1 - Discount2)

Calculations:

First discount price = ₹21,600 × (1 - 25/100) = ₹21,600 × 0.75 = ₹16,200

Second discount price = ₹16,200 × (1 - 26/100) = ₹16,200 × 0.74 = ₹11,988

∴ The selling price of the article is ₹11,988.

Given:

Marked price (MP) = Rs. 21400

First discount = 23%

Second discount = 24%

Formula Used:

Selling Price (SP) = MP × (1 - First discount%) × (1 - Second discount%)

Calculation:

First discount factor = (1 - 23/100) = 0.77

Second discount factor = (1 - 24/100) = 0.76

⇒ SP = 21400 × 0.77 × 0.76

⇒ SP = 21400 × 0.5852

⇒ SP = Rs. 12523.28

The selling price is Rs. 12523.28.

Given:

Selling Price (SP) = ₹224784

Successive Discounts = 10% and 20%

Formula used:

SP = MP × (1 - d₁) × (1 - d₂)

Where,

MP = Marked Price

d₁ = First Discount

d₂ = Second Discount

Calculation:

224784 = MP × (1 - 0.10) × (1 - 0.20)

⇒ 224784 = MP × 0.90 × 0.80

⇒ 224784 = MP × 0.72

⇒ MP = 312200

∴ The correct answer is option (4).

Given:

Riya could not decide between discount of 30% or two successive discounts of 25% and 5%, both given on shopping of ₹3,840. 

Concept used:

1. Final discount percentage after two successive discounts of A% and B% = \((A + B - {AB \over 100})\%\)

2. Discount = Marked Price × Discount%

Calculation:

Final discount% for two successive discounts of 25% and 5% = \(25 + 5 - \frac {25 × 5}{100}\) = 28.75%

Difference between discount% = 30 - 28.75 = 1.25%

Now, the difference between the discount = 3840 × 1.25% = ₹48

∴ The difference between both the discounts is ₹48.

Formula used

Single equivalent increase = x + y + [(x × y)/100]

Single equivalent decrease = x + y - [(x × y)/100] 

Calculation

Single equivalent increase of 30% each = 30 + 30 + [(30 × 30)/100]

= 30 + 30 + 9 = 69%

Single equivalent decrease of 30% each = 30 + 30 - [(30 × 30)/100]

= 51%

Required percentage = [(69 - 51)/51] × 100

= 18/51 × 100 = 35.29%

The answer is 35.29%

Given:

A shopkeeper makes a net profit of 44% on selling an article at successive discounts of 10% and 20%. 

Concept used:

1. Selling Price = Marked Price × (1 - Discount%)

2. Selling Price = Cost Price × (1 + Gain%)

Calculation:

Final discount% = \(10 + 20 - \frac {10 × 20}{100}\) = 28%

Let the marked and cost price be  = \(10 + 20 - \frac {10 × 20}{100}\) = 28% respectively.

​According to the question,

MP(1 - 28%) = CP(1 + 44%)

⇒ 0.72 × MP = 1.44 × CP

⇒ MP = 2CP

If a 15% discount is allowed then the selling price

⇒ MP(1 - 15%)

⇒ 0.85MP

⇒ 0.85 × 2CP = 1.7CP

Now, profit% = \(\frac {1.7CP - CP}{CP} × 100\%\) = 70%

∴ The net profit is 70%.

Shortcut Trick

Final discount% = \(10 + 20 - \frac {10 × 20}{100}\) = 28%

So, MP : SP = 100 : 72 

Here, shopkeeper makes a net profit of 44%

So, CP : SP = 100 : 144

Now, CP : SP : MP = 100 : 144 : 200

Now, 15% discount given then SP = 200 × 85/100 = 170

So, profit% is 70/100 × 100 = 70%

Given:

The price of a scooter increases successively by 10%, 5% and 15%.

Concept used:

Final percentage change after two successive increments of A% and B% = \((A + B + {AB \over 100})\%\)

Calculation:

Resultant increment%  = 10 + 5 + (10 × 5)/100 = 15.5%

Final increment% = 15.5 + 15 + (15.5 × 15)/100 = \(32 \frac{33}{40} \%\)

∴ The total percentage increase in the price of the scooter is \(32 \frac{33}{40} \%\).

Given:

The first discount given is 10%.

Marked price of the watch = Rs. 2750

Concept used:

Selling price = Marked price × (100 - Discount)%

Calculation:

After 1st discount amount = 2750 × 90%

⇒ 2475

Let the second discount be a%

According to the question,

2475 × (100 - a)% = 2103.75

⇒ (100 - a)/100 = 2103.75/2475

⇒ (100 - a)/100 = 210375/247500

⇒ (100 - a) = 210375/2475

⇒ (100 - a) = 187/2.2

⇒ 220 - 2.2a = 187

⇒ 220 - 187 = 2.2a

⇒ 33 = 2.2a

⇒ 15 = a

So, the second discount is 15%

∴ The second discount is 15%.

Shortcut Trick

We know, 10% = 1/10

In the 1st discount MP = 10 and SP = 9 

Let's assume in the 2nd discount MP = x SP = y

So, x : y = (9 × 2750) : (10 × 2103.75) = 20 : 17

So, the 2nd discount be 3/20 × 100 = 15%

Given:

3 Successive Discounts = 12%, 20%, 25%

Formula Used:

Equivalent discount = a + b - (a × b)/100

Where a & b are the two successive discounts. 

Calculation:

Equivalent discount of 12% & 20% = 12 + 20 - (12 × 20)/100 = 32 - 2.4 = 29.6%

Now, the equivalent discount of 29.6% and 25%

⇒ 29.6 + 25 - (29.6 × 25)/100 = 54.6 - 7.4 = 47.2%

∴ The equivalent discount of 12%, 20% & 25% is 47.2%

Hence, the correct answer is 47.2%.

Given:

Approximate single discount equivalent to three successive discounts of 25% each.

Formula Used:

Single discount equivalent to two successive discounts of a % and b %

= (a + b - \(\frac{ab}{100}\))%

Calculation:

Here, a = 25% , and b =  25 %

So, the single discount  gets, (25 + 25 - 25 × 25/100) %

⇒ (50 - 6.25) %

⇒ 43.75 %

Again,

Here, a = 43.75 % , and b =  25 %

So, the single discount  gets,

(43.75 + 25 - 43.75 × 25/100) %

⇒ (68.75 - 10.90) %

⇒ 57.81 % 

Approximate single discount is 57.81%

Shortcut Trick 

∴ Required Discount- 37/64×100= 57.81%.

Given

Three successive discounts of 15%, 20% and 25% are given.

Formula Used: 

Effective discount when two discounts are offered,

⇒ a + b - (a × b)/100

Calculation:

⇒ 15 + 20 - (15 × 20)/100

⇒ 35 - 3

⇒ 32%

⇒ 25 + 32 - (25 × 32)/100

⇒ 57 - 8

⇒ 49%

The net discount in percentage is 49%.

Given:

The equivalent discount percentage corresponding to two successive discounts of 9% and 17%

Formula Used:

Single discount equivalent to two successive discounts of a % and b %

= (a + b - \(\frac{a \space × \space b}{100}\) ) %

Calculation:

Here, a = 17 % , and b =  9 %

So, the single discount = (17 + 9 - \(\frac{17 \space × \space 9}{100}\)) %

⇒ (26 - 1.53) %

⇒ 24.47%

∴ The correct option is 4

Given:

The printed price of a TV set is ₹14,500. It is sold for ₹10,000 with two consecutive discounts.

The first discount is 10%.

Concept used:

Selling Price = Marked Price × (1 - Discount%)

Calculation:

The price becomes after the first discount = 14500 × (1 - 10%) = Rs. 13050

Let the second discount be R%.

​According to the concept,

13050(1 - R/100) = 10000

⇒ (1 - R/100) = 10000/13050

⇒ (1 - R/100) = 200/261

⇒ R/100 = 1 - 200/261

⇒ R/100 = 61/261

⇒ R = 6100/261

⇒ R = 23.371 ≈ 23.37

∴ The second discount is 23.37%.