Question
Download Solution PDFA rectifier type instrument uses a bridge rectifier and has its scale calibrated in terms of rms value of a sine wave. It indicates a voltage of 3.33 V when measuring a voltage of a triangular wave shape. Calculate the peak value of the applied voltage?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
For triangular wave shape, the peak value of voltage is:
\(V_m=2V_{avg}\)
If the meter is calibrated in terms of RMS value, then the average value is given by:
\(V_{avg}={V_o\over FF}\)
The form factor of the bridge rectifier is 1.11
Calculation
The meter uses a full wave rectifier circuit which indicates the value of 3.33 V. The form factor for full wave rectified sinusoidal waveform is 1.11
\(V_{avg}={3.33\over 1.11}=3\)
Peak voltage, \(V_m=2\times 3=6\space V\)
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