15 सेमी आणि 13 सेमी त्रिज्या असलेले दोन समकेंद्री वर्तुळ दिले आहेत. लहान वर्तुळाला स्पर्श करणाऱ्या मोठ्या वर्तुळाच्या जीवेची लांबी शोधा.

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SSC CGL 2023 Tier-I Official Paper (Held On: 18 Jul 2023 Shift 1)
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  1. 22√7
  2. \(8\sqrt{14}\)
  3. \(4\sqrt{14}\)
  4. 12√7

Answer (Detailed Solution Below)

Option 3 : \(4\sqrt{14}\)
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Detailed Solution

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दिलेले आहे:

मोठ्या वर्तुळाची त्रिज्या (R) = 15 सेमी

लहान वर्तुळाची त्रिज्या (r) = 13 सेमी

वापरलेली संकल्पना:

वर्तुळाच्या केंद्रातून जीवेपर्यंत काढलेली रेषा, जीवेला दोन भागांमध्ये विभागते.

वर्तुळाची स्पर्शिका संपर्क बिंदूवरील वर्तुळाच्या त्रिज्येला लंब असते.

पायथागोरसचे प्रमेय:

H2 = P2 + B2

येथे, H = कर्ण; P = लंब; B = पाया

गणना:

qImage64d3b6f625818518792cbb2a

येथे, O हा वर्तुळाचा केंद्रबिंदू आहे आणि PQ ही वर्तुळाची जीवा आहे.

△POR मध्ये,

⇒ OP2 = OR2 + PR2

⇒ (15)2 = (13)2 + PR2

⇒ PR2 = 225 - 169 = 56

PR = √56 = 2√14 सेमी

PQ ही स्पर्शिका आहे, म्हणून OR ⊥ PQ

PQ = PR + RQ

⇒ 2√14 + 2√14 (जसे PR = RQ)

⇒ 4√14 सेमी

4√14 सेमी हे योग्य उत्तर आहे.  

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