Question
Download Solution PDFTwo equal circles of radius 18 cm intersect each other, such that each passes through the centre of the other. The length of the common chord is _________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The radius of the circles is 18 cm
Calculation:
According to the diagram,
AD = DB
O1O2 = 18
Again O1A = O2A = 18 [Radius of the circle]
∠ADO1 = 90°
O1D = O2D = 9
AD = √(324 - 81)
⇒ (9√3)
AB = 2 × (9√3) = 18√3 = 6√27
∴ The length of the common chord is 6√27 cm.
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