Question
Download Solution PDFA, B and C can separately complete a work in 12, 15 and 20 days, respectively. They worked together 4 days. What will be the remaining work?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A, B and C can do work in 12, 15, and 20 days respectively
Formula Used:
Total work = Efficiency × Time taken
Calculation:
Total work = 60 units (LCM of 12, 15, 20)
⇒ Efficiency of A = 60/12 = 5 units/day
⇒ Efficiency of B = 60/15 = 4 units/day
⇒ Efficiency of C = 60/20 = 3 units/day
4 day's work = (5 + 4 + 3) × 4 = 48
Remaining work = (60 - 48)/60
⇒ 1/5
The remaining work is 1/5.
Last updated on Jun 13, 2025
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