Question
Download Solution PDFThe soil has a liquid limit of 50% and plastic limit of 25%, respectively. If the volumetric shrinkages at the liquid limit and plastic limit are 50% and 30%, respectively, determine the dry volume of soil, if the volume at liquid limit is 1 ml.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Volumetric shrinkage(\(V_s\)) is calculated using the following formula:
\(V_s = \frac{V - V_d}{V_d} \times 100 \)
Where:
\(V\) is the original volume.
\(V_d\) is the dried volume
Given:
At the liquid limit, the volumetric shrinkage \(V_s\) is 50%
Volume at liquid limit \(V_1\)= 1 ml
\(\frac{V_1 - V_d}{V_d} = 50\% \)
\(0.5 = \frac{V_d}{1 - V_d} \)
\(V = 1.5V_d \)
\(V_d = \frac{1}{1.5} = 0.66 \, \text{ml} \)
Dry volume of soil is 0.66 ml when the volume at the liquid limit is 1 ml.
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